14y^2+43y-21=0

Solution for 14y^2+43y-21=0 equation:

14y^2+43y-21=0

a = 14; b = 43; c = -21;
Δ = b2-4ac
Δ = 432-4·14·(-21)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-55}{2*14}=\frac{-98}{28}
=-3+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+55}{2*14}=\frac{12}{28}
=3/7
$